QOJ.ac

QOJ

#	имя пользователя	Девиз	Задачи
/	Qingyu		5829
1	larryzhong		926
2	xiaowuc1	you're a half a world away, but in my mind I whisper every single word you say	517
3	MaMengQi		459
4	ZhaoZiLong		456
5	HuangHanSheng		439
6	ZhangYiDe		435
7	GuanYunchang		432
/	flower	sqytxdy!	325
8	hydd	Qingyu txdy $\\$ $\text{If my armor breaks, I'll fuse it back together}$	312
9	Crysfly	$$f(x)=(\sum_{i=0}^{n-1}\frac{y_i}{(x-q^i)\prod_{j\ne i}(q^i-q^j)})\prod_{i=0}^{n-1}(x-q^i)$$	247
10	tricyzhkx		228
11	chenshi		215
12	zhouhuanyi		199
13	Wu_Ren		189
14	maspy		187
15	repoman	$$\prod_{i=0}^{n-1} (1+q^iz) = \sum_{i=0}^n q^{i(i-1)/2}\binom ni_q z^i$$	176
16	He_Ren		170
16	qwq	$\displaystyle \sum_{i=1}^n [i,i+1,\cdots, i+k] \pmod{10^9+7}$	170
18	alpha1022	$$\frac{1}{n_1!n_2!}(1-y)^{n_1+n_2+2} \left(\sum_{j\ge 0} y^j(t+j)^{n_1} \right) \left(\sum_{j\ge 0} y^j((j+1)-t)^{n_2} \right)$$	163
19	ckiseki		161
20	feecle6418	gyh ak ioi	160
21	Lenstar	orz Qingyu	156
21	Sa3tElSefr	leh	156
23	Appleblue17		152
24	zhangboju	短暂登上首页并即将掉下来	149
25	eyiigjkn		147
26	BeyondHeaven		138
26	hutality	$$[x^n](1-x)^{-\frac{1}{2}} \exp\left(\frac{x(1+x)}{2-2x}\right)\frac{\left(\frac{2-x}{2-2x}\right)^k}{k!}\cdot\,_0 F _1 \left(;k+1;x\left(\frac{2-x}{2-2x}\right)^2\right)$$	138
28	lmeowdn		137
29	LH	$$\|X/G\| = \frac{1}{\|G\|}\sum_{g \in G}\|X^g\|$$	135
29	Minneapolis	卷王别卷了	135
31	YaoBIG		131
32	zombie462	<b>123</b>	124
33	Sorting		123
34	not_so_organic	今晚九点，QYC 唱歌。	121
35	JohnAlfnov	Qingyu Kedavra !	119
36	whatever		116
37	std	大家好，我是来自彭博社的埃斯提迪	115
38	sdoi	$$P_{a_i}(x) = [t^{a_i}]\frac{1}{1-xF(t)}$$	111
39	zhoukangyang		110
40	DianasDog	关注嘉然，顿顿解馋	109
41	AFewSuns	$\displaystyle\sum_{n \geq 0}{(x+y)^n\frac{u^n}{n!}}=\sum_{k \geq 0}\frac{x}{x-kz}(x-kz)^k\frac{u^k}{k!}\sum_{l \geq 0}\frac{(y+kz)^l}{l!}u^l$	108
42	hos_lyric	兔	105
/	Qiuly	理论上状态数应该是 $2^{552}$，但搜一搜发现只有 $1834$ 。	104
43	xiaoyaowudi		103
44	propensity	The binary Gray code is fun, For in it strange things can be done. Fifteen, as you know, Is one, oh, oh, oh, And ten is one, one, one and one	101
45	ybw051114		100
46	LoverInTime	089年的树剖	99
47	myee	与其诺诺以顺，不若谔谔以昌	98
47	smax		98
47	wlxhkk		98
50	perspective		97
51	Baltinic	$$\rho \left ( \frac{\partial \mathbf{v}}{\partial t} + \mathbf{v} \cdot \nabla \mathbf{v} \right) = - \nabla p + \nabla \cdot \mathbf{T} + \mathbf{f}$$	92
51	DaBenZhongXiaSongKuaiDi		92
53	George_Plover		91
53	sinbad		91
55	huredomirikayatuda		90
56	testusera		88
57	little_sun		86
58	yangjiuzhi	@_silhouette_	84
59	Beevo		83
60	abdelrahman001		82
61	15867449938	$$Z_G(t_1,t_2,\ldots,t_n) = \frac{1}{\|G\|}\sum_{g \in G} t_1^{c_1(g)} t_2^{c_2(g)} \cdots t_n^{c_n(g)}$$	81
61	99pts_WA		81
63	123456	俺宣布俺是正宗滴【123456】	79
64	Chenguanlin	陈冠霖培训班现在开课，报名请私聊陈冠霖。	76
64	_silhouette_		76
66	fzj2007		75
66	Macesuted		75
68	PetroTarnavskyi		72
68	xiaojifang	大家好我是小机房，又名更衣室。	72
70	Froggygua	周转没有丁丁。	71
70	hydd_lenstar_team		71
72	winmain		70
73	triplem5ds		69
74	sagittarius_fjz	魔法少女小熊	68
75	Mr_Eight	今晚九点，whq唱歌，不见不散。	67
76	goodman		66
77	KING_UT		65
77	pretentious	$$\det(AB) = \sum_{S\in\tbinom{[n]}m} \det(A_{[m],S})\det(B_{S,[m]})$$	65
79	neko_nyaa		63
79	SuffixTree		63
81	Arraiter		62
81	CharlieVinnie	You fly away so proudly, away from my summer. Slient words of praying, all these years repeating	62
81	littlesummer		62
81	MIT01		62
81	znstz		62
86	flywatre		61
86	skittles1412		61
86	taniya	$$\prod_{n=1}^\infty (1-x^n)=\sum_{k=-\infty}^\infty(-1)^kx^{\frac{k(3k-1)}{2}}=\sum_{k=0}^\infty(-1)^kx^{\frac{k(3k\pm 1)}{2}}$$	61
89	00	$$ e^x = \sum_{n=0} \frac{x^n}{n!} $$	60
89	qinjianbin		60
91	275307894a		59
91	Iris	?	59
91	QAQQWQ		59
94	Zuqa		57
95	JackF	______是不是贺子	56
95	magicduck		56
95	yh		56