QOJ.ac

QOJ

#	Username	Motto	Solved
/	Qingyu	永眠	6620
1	larryzhong		982
2	MaMengQi		735
3	ZhangYiDe		724
4	ZhaoZiLong		722
5	HuangHanSheng		710
6	GuanYunchang		702
7	xiaowuc1	you're a half a world away, but in my mind I whisper every single word you say	527
8	hos_lyric	$$\left[\frac{x^n}{n!} q^{K-1}\right] \frac{(\mathrm{e}^{rx} - 1) (q + r + \mathrm{e}^{rx} + q \mathrm{e}^{rx} - r \mathrm{e}^{rx} + 1)}{(q + 1) (r - \mathrm{e}^{2rx} + r \mathrm{e}^{2rx} + 1)}$$	475
9	flower	qingyu txdy!	357
10	Crysfly	sunflower-addicted	355
11	zhouhuanyi		316
12	hydd	Qingyu txdy $\\$ $\text{If my armor breaks, I'll fuse it back together}$	309
13	maspy		252
14	PetroTarnavskyi		251
15	tricyzhkx		248
16	He_Ren		237
17	sdoi	$$P_{a_i}(x) = [t^{a_i}]\frac{1}{1-xF(t)}$$	234
18	ckiseki		229
19	lmeowdn		219
20	chenshi		218
21	Sorting	ㅗ오ㅗ	214
22	PhantomThreshold		212
22	ucup-team004		212
24	repoman	$$\prod_{i=0}^{n-1} (1+q^iz) = \sum_{i=0}^n q^{i(i-1)/2}\binom ni_q z^i$$	208
25	qwq	$\displaystyle \sum_{i=1}^n [i,i+1,\cdots, i+k] \pmod{10^9+7}$	198
26	Wu_Ren		192
27	lmq26052003		177
28	AFewSuns	$\displaystyle\sum_{n \geq 0}{(x+y)^n\frac{u^n}{n!}}=\sum_{k \geq 0}\frac{x}{x-kz}(x-kz)^k\frac{u^k}{k!}\sum_{l \geq 0}\frac{(y+kz)^l}{l!}u^l$	173
/	alpha1022	$$\frac{1}{n_1!n_2!}(1-y)^{n_1+n_2+2} \left(\sum_{j\ge 0} y^j(t+j)^{n_1} \right) \left(\sum_{j\ge 0} y^j((j+1)-t)^{n_2} \right)$$	171
29	myee	与其诺诺以顺，不若谔谔以昌	171
30	eyiigjkn		170
30	feecle6418	gyh ak ioi	170
32	Sa3tElSefr	leh	157
33	Lenstar	orz Qingyu	154
34	Appleblue17		152
35	zhangboju	短暂登上首页并即将掉下来	149
36	KKT89		144
37	BeyondHeaven		143
37	qzez		143
39	SolitaryDream		141
40	zhoukangyang		139
41	hutality	$$[x^n](1-x)^{-\frac{1}{2}} \exp\left(\frac{x(1+x)}{2-2x}\right)\frac{\left(\frac{2-x}{2-2x}\right)^k}{k!}\cdot\,_0 F _1 \left(;k+1;x\left(\frac{2-x}{2-2x}\right)^2\right)$$	138
42	LH	$$\|X/G\| = \frac{1}{\|G\|}\sum_{g \in G}\|X^g\|$$	136
42	ucup-team1209		136
44	Minneapolis	卷王别卷了	135
45	LoverInTime	089年的树剖	134
/	Qiuly	fendou	134
46	YaoBIG		131
47	wlxhkk		126
48	JohnAlfnov	Qingyu Kedavra !	124
49	99pts_WA		123
49	triplem5ds		123
49	zombie462	<b>123</b>	123
52	Beevo		121
52	new_dawn_2		121
52	not_so_organic	今晚九点，QYC 唱歌。	121
55	275307894a		120
56	whatever		118
56	znstz		118
58	ybw051114		115
59	waifuSenpai		114
60	DianasDog	关注嘉然，顿顿解馋	113
60	neko_nyaa		113
62	xiaoyaowudi		110
63	bulijiojiodibuliduo		104
64	smax		102
/	yzhang	如果结果不如你所愿，就在尘埃落定前奋力一搏	102
65	8BQube		101
65	Forever_Young		101
65	propensity	The binary Gray code is fun, For in it strange things can be done. Fifteen, as you know, Is one, oh, oh, oh, And ten is one, one, one and one	101
65	UrgantTeam		101
69	sinbad		100
70	DitaMirika		99
71	lpf		98
72	perspective	$$\sqrt{\pi n} \lesssim \mathbb E[\mathrm{depth}] \leq O((n\log n)^{1/2})$$	97
73	ucup-team870		94
74	Baltinic	$$\rho \left ( \frac{\partial \mathbf{v}}{\partial t} + \mathbf{v} \cdot \nabla \mathbf{v} \right) = - \nabla p + \nabla \cdot \mathbf{T} + \mathbf{f}$$	93
74	SorahISA		93
76	DaBenZhongXiaSongKuaiDi		92
77	George_Plover		91
78	huredomirikayatuda		90
79	bashkort	Lost time is never found again.	89
79	chenchi		89
79	hyforces		89
79	rgnerdplayer		89
79	Scintilla		89
84	testusera		88
85	karuna		86
85	little_sun		86
85	ucup-team607		86
85	xaphoenix		86
89	youngsystem		84
90	yangjiuzhi	@_silhouette_	83
91	abdelrahman001		82
92	15867449938	$$Z_G(t_1,t_2,\ldots,t_n) = \frac{1}{\|G\|}\sum_{g \in G} t_1^{c_1(g)} t_2^{c_2(g)} \cdots t_n^{c_n(g)}$$	81
92	yyyyxh		81
94	123456	俺宣布俺是正宗滴【123456】	80
95	fzj2007		78
96	Chenguanlin	陈冠霖培训班现在开课，报名请私聊陈冠霖。	76