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#用户名格言通过数
1hos_lyric$$\left[\frac{x^n}{n!} q^{K-1}\right] \frac{(\mathrm{e}^{rx} - 1) (q + r + \mathrm{e}^{rx} + q \mathrm{e}^{rx} - r \mathrm{e}^{rx} + 1)}{(q + 1) (r - \mathrm{e}^{2rx} + r \mathrm{e}^{2rx} + 1)}$$1077
2larryzhong983
3ucup-team1005大家好,我是 C++ 高手,今天来点大家想看的东西。$$ \begin{aligned} &\texttt{sort(Ring.begin(), Ring.end());} \\ &\texttt{sort(Chain.begin(), Chain.begin(), [](int x, int y) \{return x > y;\});} \end{aligned}$$751
4PetroTarnavskyiWhy haven't you registered at https://algotester.com/en yet? 🤨710
5zhouhuanyi623
6Crysfly加训610
7ckiseki卷不动了609
8ucup-team2335563
9PhantomThreshold551
10xiaowuc1you're a half a world away, but in my mind I whisper every single word you say532
11dXqwqTo the cosmic524
12lmq26052003515
13grass8cow505
14SolitaryDream462
15ucup-team1209我不是可爱小青鱼442
16ucup-team087438
17ucup-team1198431
18ucup-team004421
19LoverInTime089年的树剖401
20ucup-team2880397
21flower378
22275307894a369
23maspyUniversal Cup Upsol部366
24qiuzx362
25ucup-team1878354
26MoRanSky无论过去 不问将来333
27hyforces永远不够328
28Kevin5307$$ \frac{1}{1-x}\sum_{k=1}^\infty\frac{x^k}{1-\frac{x-x^{k+1}}{1-x}} $$327
28ucup-team052327
30lmeowdn311
31hyddQingyu txdy $\\$ If my armor breaks, I'll fuse it back together310
31waifuSenpai310
33ucup-team1004方队akioi309
33ucup-team864309
35ucup-team191302
36ucup-team987301
37Lynkcat298
38Sortingㅗ오ㅗ 293
39james1BadCreeper他明白 他明白 我给不起287
39ucup-team159287
41alpha1022$$\frac{1}{n_1!n_2!}(1-y)^{n_1+n_2+2} \left(\sum_{j\ge 0} y^j(t+j)^{n_1} \right) \left(\sum_{j\ge 0} y^j((j+1)-t)^{n_2} \right)$$286
42ucup-team266280
43znstz277
44ucup-team1134276
45ucup-team133270
46AFewSuns$\displaystyle\sum_{n \geq 0}{(x+y)^n\frac{u^n}{n!}}=\sum_{k \geq 0}\frac{x}{x-kz}(x-kz)^k\frac{u^k}{k!}\sum_{l \geq 0}\frac{(y+kz)^l}{l!}u^l$269
47bachbeo2007266
47ezteam1266
49ucup-team1447没队要263
50ucup-team253259
51ucup-team138252
51zhaohaikun252
53tricyzhkx249
54ucup-team130246
55ucup-team267哈姆。242
56iee239
57sdoi$$P_{a_i}(x) = [t^{a_i}]\frac{1}{1-xF(t)}$$237
57ucup-team025237
59He_Ren236
59ucup-team134236
61KKT89233
61ucup-team112233
63ucup-team122229
64ucup-team180226
658BQube222
65ucup-team216222
67chenshi218
68karuna217
69repoman$$\prod_{i=0}^{n-1} (1+q^iz) = \sum_{i=0}^n q^{i(i-1)/2}\binom ni_q z^i$$215
69ushg8877215
71ucup-team1293214
71ucup-team870214
73zhoukangyang213
74ucup-team228212
75ucup-team3215206
76do_while_true204
77new_dawn_2203
77ucup-team1525203
79ucup-team123202
79ucup-team244202
81kevinyang201
82qwq$\displaystyle \sum_{i=1}^n [i,i+1,\cdots, i+k] \pmod{10^9+7}$199
82ship2077199
82ucup-team1126199
85ucup-team029197
86ucup-team1191196
87Wu_Ren194
88JohnAlfnovQingyu Kedavra ! 193
89ucup-team2307192
90ucup-team311191
91_map_map<problem_statement,vector<pair<oj,problem_id>>>190
92ucup-team026188
92ucup-team045188
92ucup-team1055188
95DitaMirika184
95myee与其诺诺以顺,不若谔谔以昌184
97chenxinyang2006179
98bulijiojiodibuliduo178
98monstersqwq178
100feecle6418gyh ak ioi177
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