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#用戶名格言通過數
1xiaowuc1you're a half a world away, but in my mind I whisper every single word you say1307
2hos_lyric$$\left[\frac{x^n}{n!} q^{K-1}\right] \frac{(\mathrm{e}^{rx} - 1) (q + r + \mathrm{e}^{rx} + q \mathrm{e}^{rx} - r \mathrm{e}^{rx} + 1)}{(q + 1) (r - \mathrm{e}^{2rx} + r \mathrm{e}^{2rx} + 1)}$$1185
3ucup-team1005沉舟侧畔千帆过1035
4larryzhong983
5PetroTarnavskyiWhy haven't you registered at https://algotester.com/en yet? 🤨798
6Crysfly我还能为你驻足到何时686
7zhouhuanyi679
8PhantomThreshold669
9ckiseki卷不动了608
10qiuzx605
11ucup-team2335562
12dXqwqI can see the Light on you, You can see the Right on me554
13ucup-team004545
14lmq26052003534
15grass8cow525
16ucup-team087517
17ucup-team1198515
18maspyUniversal Cup Upsol部467
19SolitaryDream462
20ucup-team052459
21ucup-team1878446
22ucup-team1209我不是可爱小青鱼442
23ucup-team2880431
24LoverInTime089年的树剖401
25ucup-team1004方队akioi398
26275307894a396
27ship2077387
28flower377
29Kevin5307$$ \frac{1}{1-x}\sum_{k=1}^\infty\frac{x^k}{1-\frac{x-x^{k+1}}{1-x}} $$367
30hyforces永远不够366
31ucup-team159364
31ucup-team987364
33bachbeo2007349
34ucup-team191343
35ucup-team864340
36MoRanSky无论过去 不问将来337
37ucup-team1134332
38ucup-team130322
38ucup-team253322
40ucup-team133319
41waifuSenpai317
42lmeowdn316
43hyddQingyu txdy $\\$ If my armor breaks, I'll fuse it back together310
44Lynkcat300
45Sortingㅗ오ㅗ 299
46ucup-team138290
46ucup-team266290
48ucup-team025289
48ucup-team112289
50james1BadCreeper他明白 他明白 我给不起287
51alpha1022$$\frac{1}{n_1!n_2!}(1-y)^{n_1+n_2+2} \left(\sum_{j\ge 0} y^j(t+j)^{n_1} \right) \left(\sum_{j\ge 0} y^j((j+1)-t)^{n_2} \right)$$286
52znstz278
53AFewSuns$\displaystyle\sum_{n \geq 0}{(x+y)^n\frac{u^n}{n!}}=\sum_{k \geq 0}\frac{x}{x-kz}(x-kz)^k\frac{u^k}{k!}\sum_{l \geq 0}\frac{(y+kz)^l}{l!}u^l$269
54ezteam1267
54ucup-team311267
56ucup-team1525266
57ucup-team1447没队要262
58ucup-team216260
59ucup-team180257
59zhaohaikun257
61tricyzhkx250
62ucup-team2307247
63KKT89246
63ucup-team244246
65ucup-team267哈姆。242
65ucup-team3215242
67ucup-team122241
67zhoukangyang241
69ucup-team134240
70iee238
71He_Ren237
71sdoi$$P_{a_i}(x) = [t^{a_i}]\frac{1}{1-xF(t)}$$237
738BQube222
74chenshi221
75karuna220
75kevinyang220
77ucup-team2818219
78ucup-team3519217
79ucup-team870215
79ushg8877215
81chenxinyang2006214
81repoman$$\prod_{i=0}^{n-1} (1+q^iz) = \sum_{i=0}^n q^{i(i-1)/2}\binom ni_q z^i$$214
81ucup-team1293214
84ucup-team1123213
85ucup-team228211
86JohnAlfnovQingyu Kedavra ! 210
86PlentyOfPenalty高亮的是我们,我们是青鱼家军!210
88do_while_true203
88new_dawn_2203
90DaiRuiChen007202
90ucup-team045202
92Forever_Young201
92Max_s_xaM201
92ucup-team1002201
92ucup-team123201
96rgnerdplayer199
96ucup-team1126199
98qwq$\displaystyle \sum_{i=1}^n [i,i+1,\cdots, i+k] \pmod{10^9+7}$198
99ucup-team029197
100ucup-team008196
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