QOJ.ac

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AFewSuns

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2447

Contribution

8

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Default

Motto

$\displaystyle\sum_{n \geq 0}{(x+y)^n\frac{u^n}{n!}}=\sum_{k \geq 0}\frac{x}{x-kz}(x-kz)^k\frac{u^k}{k!}\sum_{l \geq 0}\frac{(y+kz)^l}{l!}u^l$

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Accepted problems:269 problems

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Tried problems:5 problems

6201877441155507647

Virtual Participations:8 contests

NameStart time
Public NOIP Round #1 (Div. 2, 普及)2022-09-16 22:38:13
Public Round #72022-08-06 13:04:14
Public Round #42022-07-21 11:27:51
Public Round #52022-07-07 08:28:02
Public Round #62022-07-07 08:27:55
Public Easy Round #22022-05-06 23:01:42
Public Easy Round #12022-04-23 16:49:42
Public Round #32022-04-14 17:59:57