QOJ.ac

QOJ

#	Username	Motto	Solved
/	Qingyu		5885
1	larryzhong		931
2	xiaowuc1	you're a half a world away, but in my mind I whisper every single word you say	519
3	MaMengQi		462
4	ZhaoZiLong		459
5	HuangHanSheng		442
6	ZhangYiDe		440
7	GuanYunchang		437
/	flower	qingyu txdy!	334
8	hydd	Qingyu txdy $\\$ $\text{If my armor breaks, I'll fuse it back together}$	312
9	Crysfly	$$f(x)=(\sum_{i=0}^{n-1}\frac{y_i}{(x-q^i)\prod_{j\ne i}(q^i-q^j)})\prod_{i=0}^{n-1}(x-q^i)$$	254
10	tricyzhkx		230
11	chenshi		216
12	zhouhuanyi		199
13	maspy		193
14	Wu_Ren		189
15	He_Ren		183
16	repoman	$$\prod_{i=0}^{n-1} (1+q^iz) = \sum_{i=0}^n q^{i(i-1)/2}\binom ni_q z^i$$	176
17	qwq	$\displaystyle \sum_{i=1}^n [i,i+1,\cdots, i+k] \pmod{10^9+7}$	170
18	alpha1022	$$\frac{1}{n_1!n_2!}(1-y)^{n_1+n_2+2} \left(\sum_{j\ge 0} y^j(t+j)^{n_1} \right) \left(\sum_{j\ge 0} y^j((j+1)-t)^{n_2} \right)$$	163
19	ckiseki		161
20	feecle6418	gyh ak ioi	160
21	Lenstar	orz Qingyu	156
21	Sa3tElSefr	leh	156
23	Appleblue17		152
24	eyiigjkn		151
25	zhangboju	短暂登上首页并即将掉下来	149
26	lmeowdn		147
27	BeyondHeaven		138
27	hutality	$$[x^n](1-x)^{-\frac{1}{2}} \exp\left(\frac{x(1+x)}{2-2x}\right)\frac{\left(\frac{2-x}{2-2x}\right)^k}{k!}\cdot\,_0 F _1 \left(;k+1;x\left(\frac{2-x}{2-2x}\right)^2\right)$$	138
29	LH	$$\|X/G\| = \frac{1}{\|G\|}\sum_{g \in G}\|X^g\|$$	135
29	Minneapolis	卷王别卷了	135
31	std	大家好，我是来自彭博社的埃斯提迪	133
32	YaoBIG		131
33	zombie462	<b>123</b>	124
34	Sorting		123
35	not_so_organic	今晚九点，QYC 唱歌。	121
36	JohnAlfnov	Qingyu Kedavra !	119
/	Qiuly	失望，难过，愤怒。太伤心了！	118
37	whatever		116
38	hos_lyric	兔	114
38	zhoukangyang		114
40	sdoi	$$P_{a_i}(x) = [t^{a_i}]\frac{1}{1-xF(t)}$$	111
41	AFewSuns	$\displaystyle\sum_{n \geq 0}{(x+y)^n\frac{u^n}{n!}}=\sum_{k \geq 0}\frac{x}{x-kz}(x-kz)^k\frac{u^k}{k!}\sum_{l \geq 0}\frac{(y+kz)^l}{l!}u^l$	110
42	DianasDog	关注嘉然，顿顿解馋	109
43	xiaoyaowudi		106
44	propensity	The binary Gray code is fun, For in it strange things can be done. Fifteen, as you know, Is one, oh, oh, oh, And ten is one, one, one and one	101
44	wlxhkk		101
46	LoverInTime	089年的树剖	100
46	ybw051114		100
48	myee	与其诺诺以顺，不若谔谔以昌	99
49	smax		98
50	perspective		97
51	Baltinic	$$\rho \left ( \frac{\partial \mathbf{v}}{\partial t} + \mathbf{v} \cdot \nabla \mathbf{v} \right) = - \nabla p + \nabla \cdot \mathbf{T} + \mathbf{f}$$	92
51	DaBenZhongXiaSongKuaiDi		92
53	George_Plover		91
53	sinbad		91
55	huredomirikayatuda		90
56	testusera		88
57	little_sun		86
58	99pts_WA		85
59	yangjiuzhi	@_silhouette_	84
60	Beevo		83
61	abdelrahman001		82
62	15867449938	$$Z_G(t_1,t_2,\ldots,t_n) = \frac{1}{\|G\|}\sum_{g \in G} t_1^{c_1(g)} t_2^{c_2(g)} \cdots t_n^{c_n(g)}$$	81
63	123456	俺宣布俺是正宗滴【123456】	79
64	Chenguanlin	陈冠霖培训班现在开课，报名请私聊陈冠霖。	76
64	_silhouette_		76
66	fzj2007		75
66	Macesuted		75
68	PetroTarnavskyi		72
68	xiaojifang	大家好我是小机房，又名更衣室。	72
70	Froggygua	周转没有丁丁。	71
70	hydd_lenstar_team		71
72	winmain		70
73	triplem5ds		69
74	sagittarius_fjz	魔法少女小熊	68
75	Mr_Eight	今晚九点，whq唱歌，不见不散。	67
75	znstz		67
77	goodman		66
78	KING_UT		65
78	pretentious	$$\det(AB) = \sum_{S\in\tbinom{[n]}m} \det(A_{[m],S})\det(B_{S,[m]})$$	65
80	CharlieVinnie	You fly away so proudly, away from my summer. Slient words of praying, all these years repeating	63
80	neko_nyaa		63
80	SuffixTree		63
83	Arraiter		62
83	littlesummer		62
83	MIT01		62
86	00	$$ e^x = \sum_{n=0} \frac{x^n}{n!} $$	61
86	275307894a		61
86	flywatre		61
86	skittles1412		61
86	taniya	$$\prod_{n=1}^\infty (1-x^n)=\sum_{k=-\infty}^\infty(-1)^kx^{\frac{k(3k-1)}{2}}=\sum_{k=0}^\infty(-1)^kx^{\frac{k(3k\pm 1)}{2}}$$	61
91	qinjianbin		60
92	Iris	?	59
92	QAQQWQ		59
94	magicduck		57
94	Zuqa		57
96	JackF	______是不是贺子	56
96	yh		56