QOJ.ac

QOJ

#	Username	Motto	Solved
/	Qingyu	永眠	6589
1	larryzhong		982
2	MaMengQi		708
3	ZhangYiDe		703
4	ZhaoZiLong		696
5	HuangHanSheng		685
6	GuanYunchang		681
7	xiaowuc1	you're a half a world away, but in my mind I whisper every single word you say	527
8	hos_lyric	$$\left[\frac{x^n}{n!} q^{K-1}\right] \frac{(\mathrm{e}^{rx} - 1) (q + r + \mathrm{e}^{rx} + q \mathrm{e}^{rx} - r \mathrm{e}^{rx} + 1)}{(q + 1) (r - \mathrm{e}^{2rx} + r \mathrm{e}^{2rx} + 1)}$$	465
9	flower	qingyu txdy!	357
10	Crysfly	sunflower-addicted	349
11	hydd	Qingyu txdy $\\$ $\text{If my armor breaks, I'll fuse it back together}$	309
12	zhouhuanyi		300
13	maspy		252
14	PetroTarnavskyi		251
15	tricyzhkx		248
16	He_Ren		237
17	sdoi	$$P_{a_i}(x) = [t^{a_i}]\frac{1}{1-xF(t)}$$	234
18	ckiseki		229
19	chenshi		218
20	lmeowdn		213
21	Sorting	ㅗ오ㅗ	212
22	ucup-team004		210
23	repoman	$$\prod_{i=0}^{n-1} (1+q^iz) = \sum_{i=0}^n q^{i(i-1)/2}\binom ni_q z^i$$	208
24	PhantomThreshold		204
25	qwq	$\displaystyle \sum_{i=1}^n [i,i+1,\cdots, i+k] \pmod{10^9+7}$	198
26	Wu_Ren		192
27	AFewSuns	$\displaystyle\sum_{n \geq 0}{(x+y)^n\frac{u^n}{n!}}=\sum_{k \geq 0}\frac{x}{x-kz}(x-kz)^k\frac{u^k}{k!}\sum_{l \geq 0}\frac{(y+kz)^l}{l!}u^l$	171
/	alpha1022	$$\frac{1}{n_1!n_2!}(1-y)^{n_1+n_2+2} \left(\sum_{j\ge 0} y^j(t+j)^{n_1} \right) \left(\sum_{j\ge 0} y^j((j+1)-t)^{n_2} \right)$$	171
27	myee	与其诺诺以顺，不若谔谔以昌	171
29	eyiigjkn		170
29	feecle6418	gyh ak ioi	170
31	lmq26052003		159
32	Sa3tElSefr	leh	157
33	Lenstar	orz Qingyu	154
34	Appleblue17		152
35	zhangboju	短暂登上首页并即将掉下来	149
36	BeyondHeaven		143
37	zhoukangyang		139
38	hutality	$$[x^n](1-x)^{-\frac{1}{2}} \exp\left(\frac{x(1+x)}{2-2x}\right)\frac{\left(\frac{2-x}{2-2x}\right)^k}{k!}\cdot\,_0 F _1 \left(;k+1;x\left(\frac{2-x}{2-2x}\right)^2\right)$$	138
39	LH	$$\|X/G\| = \frac{1}{\|G\|}\sum_{g \in G}\|X^g\|$$	136
40	Minneapolis	卷王别卷了	135
/	Qiuly	fendou	132
41	YaoBIG		131
42	SolitaryDream		128
43	wlxhkk		126
44	JohnAlfnov	Qingyu Kedavra !	124
44	LoverInTime	089年的树剖	124
44	qzez		124
47	99pts_WA		123
47	ucup-team1209		123
47	zombie462	<b>123</b>	123
50	not_so_organic	今晚九点，QYC 唱歌。	121
51	275307894a		118
51	whatever		118
53	znstz		116
54	ybw051114		115
55	DianasDog	关注嘉然，顿顿解馋	113
55	new_dawn_2		113
57	neko_nyaa		112
58	triplem5ds		111
59	xiaoyaowudi		110
60	Beevo		107
61	bulijiojiodibuliduo		104
62	smax		102
62	waifuSenpai		102
64	8BQube		101
64	propensity	The binary Gray code is fun, For in it strange things can be done. Fifteen, as you know, Is one, oh, oh, oh, And ten is one, one, one and one	101
64	UrgantTeam		101
67	sinbad		100
68	lpf		98
69	perspective	$$\sqrt{\pi n} \lesssim \mathbb E[\mathrm{depth}] \leq O((n\log n)^{1/2})$$	97
/	yzhang	如果结果不如你所愿，就在尘埃落定前奋力一搏	96
70	Baltinic	$$\rho \left ( \frac{\partial \mathbf{v}}{\partial t} + \mathbf{v} \cdot \nabla \mathbf{v} \right) = - \nabla p + \nabla \cdot \mathbf{T} + \mathbf{f}$$	93
71	DaBenZhongXiaSongKuaiDi		92
72	DitaMirika		91
72	George_Plover		91
72	SorahISA		91
75	huredomirikayatuda		90
76	bashkort	Lost time is never found again.	89
76	chenchi		89
76	hyforces		89
76	rgnerdplayer		89
76	Scintilla		89
81	testusera		88
82	little_sun		86
82	xaphoenix		86
84	youngsystem		84
85	yangjiuzhi	@_silhouette_	83
86	abdelrahman001		82
86	Forever_Young		82
88	15867449938	$$Z_G(t_1,t_2,\ldots,t_n) = \frac{1}{\|G\|}\sum_{g \in G} t_1^{c_1(g)} t_2^{c_2(g)} \cdots t_n^{c_n(g)}$$	81
88	yyyyxh		81
90	123456	俺宣布俺是正宗滴【123456】	80
91	fzj2007		78
91	karuna		78
93	Chenguanlin	陈冠霖培训班现在开课，报名请私聊陈冠霖。	76
93	LFCode	无限拓展的玛瑙星空之下，少女伫立着倾听风的声音。	76
95	Macesuted		75
96	batrr		74