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#UsernameMottoSolved
1hos_lyric$$\left[\frac{x^n}{n!} q^{K-1}\right] \frac{(\mathrm{e}^{rx} - 1) (q + r + \mathrm{e}^{rx} + q \mathrm{e}^{rx} - r \mathrm{e}^{rx} + 1)}{(q + 1) (r - \mathrm{e}^{2rx} + r \mathrm{e}^{2rx} + 1)}$$1058
2larryzhong983
3PetroTarnavskyiWhy haven't you registered at https://algotester.com/en yet? 🤨651
4ucup-team1005大家好,我是 C++ 高手,今天来点大家想看的东西。$$ \begin{aligned} &\texttt{sort(Ring.begin(), Ring.end());} \\ &\texttt{sort(Chain.begin(), Chain.begin(), [](int x, int y) \{return x > y;\});} \end{aligned}$$638
5zhouhuanyi613
6ckiseki卷不动了609
7Crysfly加训597
8xiaowuc1you're a half a world away, but in my mind I whisper every single word you say532
9dXqwqTo the cosmic524
10ucup-team2335505
11lmq26052003504
12PhantomThreshold488
13SolitaryDream462
14ucup-team1209我不是可爱小青鱼442
15grass8cow427
16ucup-team087425
17ucup-team004420
18LoverInTime089年的树剖401
19ucup-team2880396
20ucup-team1198384
21flower380
22maspyUniversal Cup Upsol部366
23ucup-team1878338
24MoRanSky无论过去 不问将来333
25275307894a330
26qiuzx311
27hyddQingyu txdy $\\$ If my armor breaks, I'll fuse it back together310
27waifuSenpai310
29Kevin5307$$ \frac{1}{1-x}\sum_{k=1}^\infty\frac{x^k}{1-\frac{x-x^{k+1}}{1-x}} $$309
30ucup-team987301
31Sortingㅗ오ㅗ 293
32lmeowdn292
32ucup-team864292
34hyforces永远不够291
35Lynkcat290
36ucup-team191287
37ucup-team266280
37znstz280
39ucup-team133270
40alpha1022$$\frac{1}{n_1!n_2!}(1-y)^{n_1+n_2+2} \left(\sum_{j\ge 0} y^j(t+j)^{n_1} \right) \left(\sum_{j\ge 0} y^j((j+1)-t)^{n_2} \right)$$269
41AFewSuns$\displaystyle\sum_{n \geq 0}{(x+y)^n\frac{u^n}{n!}}=\sum_{k \geq 0}\frac{x}{x-kz}(x-kz)^k\frac{u^k}{k!}\sum_{l \geq 0}\frac{(y+kz)^l}{l!}u^l$266
42ezteam1265
42ucup-team1004方队akioi265
44bachbeo2007264
44ucup-team1134264
46ucup-team159261
47james1BadCreeper他明白 他明白 我给不起256
48tricyzhkx249
48ucup-team1447没队要249
50zhaohaikun246
51ucup-team253243
52ucup-team267哈姆。241
53sdoi$$P_{a_i}(x) = [t^{a_i}]\frac{1}{1-xF(t)}$$237
54He_Ren236
54ucup-team134236
56KKT89233
56ucup-team112233
56ucup-team130233
59iee232
60ucup-team122229
61ucup-team138228
62ucup-team025227
63ucup-team180226
648BQube222
65chenshi218
66repoman$$\prod_{i=0}^{n-1} (1+q^iz) = \sum_{i=0}^n q^{i(i-1)/2}\binom ni_q z^i$$215
66ucup-team052215
66ushg8877215
69ucup-team216214
69zhoukangyang214
71ucup-team1293213
72ucup-team228212
73ucup-team870210
74new_dawn_2203
75ucup-team123202
76karuna201
76kevinyang201
78qwq$\displaystyle \sum_{i=1}^n [i,i+1,\cdots, i+k] \pmod{10^9+7}$199
78ucup-team1126199
80ucup-team029197
81ucup-team1191196
82Wu_Ren194
83ship2077193
83ucup-team244193
85do_while_true191
86ucup-team3215190
87DitaMirika189
88ucup-team026188
88ucup-team1055188
90JohnAlfnovQingyu Kedavra ! 186
91myee与其诺诺以顺,不若谔谔以昌184
92_map_map<problem_statement,vector<pair<oj,problem_id>>>179
92ucup-team311179
94bulijiojiodibuliduo178
94ucup-team045178
96feecle6418gyh ak ioi177
97chenxinyang2006172
98mendicillin2171
99eyiigjkn170
100ucup-team173167
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