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#UsernameMottoSolved
1larryzhong983
2hos_lyric$$\left[\frac{x^n}{n!} q^{K-1}\right] \frac{(\mathrm{e}^{rx} - 1) (q + r + \mathrm{e}^{rx} + q \mathrm{e}^{rx} - r \mathrm{e}^{rx} + 1)}{(q + 1) (r - \mathrm{e}^{2rx} + r \mathrm{e}^{2rx} + 1)}$$811
3zhouhuanyi530
4xiaowuc1you're a half a world away, but in my mind I whisper every single word you say529
5ckiseki528
6Crysfly482
7PetroTarnavskyiWhy haven't you registered at https://algotester.com/en yet? 🤨471
8PhantomThreshold449
9ucup-team1005大家好,我是 C++20,今天来点大家想看的东西。$$ \begin{aligned} &\texttt{ios::sync_with_stdio(false);} \\ &\texttt{int T; cin >> T;} \\ &\texttt{while (T--) \{ scanf("%s", s + 1); ... \}} \end{aligned}$$385
10flower373
11maspyUniversal Cup Upsol部363
12lmq26052003359
13SolitaryDream334
14ucup-team087312
15hyddQingyu txdy $\\$ $\text{If my armor breaks, I'll fuse it back together}$309
16ucup-team004300
17ucup-team1209我不是可爱小青鱼278
18waifuSenpai275
19LoverInTime089年的树剖274
20ucup-team1878253
21lmeowdn251
22tricyzhkx250
23275307894a248
24Sortingㅗ오ㅗ 240
25sdoi$$P_{a_i}(x) = [t^{a_i}]\frac{1}{1-xF(t)}$$238
26He_Ren237
27AFewSuns$\displaystyle\sum_{n \geq 0}{(x+y)^n\frac{u^n}{n!}}=\sum_{k \geq 0}\frac{x}{x-kz}(x-kz)^k\frac{u^k}{k!}\sum_{l \geq 0}\frac{(y+kz)^l}{l!}u^l$227
28chenshi218
29repoman$$\prod_{i=0}^{n-1} (1+q^iz) = \sum_{i=0}^n q^{i(i-1)/2}\binom ni_q z^i$$215
30ucup-team266214
31ucup-team870210
32ucup-team1198206
33bachbeo2007205
33KKT89205
35znstz204
36ucup-team987202
37qwq$\displaystyle \sum_{i=1}^n [i,i+1,\cdots, i+k] \pmod{10^9+7}$199
38qiuzx197
39ucup-team191196
40Wu_Ren194
41alpha1022$$\frac{1}{n_1!n_2!}(1-y)^{n_1+n_2+2} \left(\sum_{j\ge 0} y^j(t+j)^{n_1} \right) \left(\sum_{j\ge 0} y^j((j+1)-t)^{n_2} \right)$$193
42ucup-team026187
42ucup-team1447没队要187
44ucup-team133186
44ucup-team138186
46myee与其诺诺以顺,不若谔谔以昌184
46zhaohaikun184
488BQube183
49ucup-team134181
49ucup-team159181
51ucup-team1134180
52new_dawn_2178
53ucup-team864174
54eyiigjkn171
54ucup-team122171
56feecle6418gyh ak ioi170
57ucup-team1126169
58zhoukangyang168
59ucup-team112158
59ucup-team216158
61hyforces永远不够157
61Sa3tElSefrleh157
63ucup-team130156
63ushg8877156
65Lenstarorz Qingyu154
66ucup-team2880153
67Appleblue17152
67ucup-team025152
69qzez151
69ucup-team1293151
71JohnAlfnovQingyu Kedavra ! 150
71ucup-team180150
73ucup-team1376CJOIers?149
73zhangboju短暂登上首页并即将掉下来149
75ucup-team088148
75ucup-team253148
77ucup-team029146
77ucup-team1004方队akioi146
79ucup-team267哈姆。145
80BeyondHeaven143
81PlentyOfPenalty高亮的是我们,我们是青鱼家军!142
82grass8cow你怎么知道我进卷题榜前100了141
82ucup-team1055141
84SoyTony真実はいつもひとつ139
85hutality$$[x^n](1-x)^{-\frac{1}{2}} \exp\left(\frac{x(1+x)}{2-2x}\right)\frac{\left(\frac{2-x}{2-2x}\right)^k}{k!}\cdot\,_0 F _1 \left(;k+1;x\left(\frac{2-x}{2-2x}\right)^2\right)$$138
86ezteam1137
87LH$$|X/G| = \frac{1}{|G|}\sum_{g \in G}|X^g|$$136
87Minneapolis卷王别卷了136
87ucup-team123136
90mendicillin2135
90triplem5ds135
90ucup-team878135
93YaoBIG134
94Beevo133
95ucup-team991132
96houzhiyuan130
96Lynkcat130
96ucup-team228130
99Forever_Young128
99jrjyy128
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