QOJ - QOJ.ac

#	Username	Motto	Solved
/	Qingyu	ღ花花ღ	5520
1	larryzhong		816
2	xiaowuc1	you're a half a world away, but in my mind I whisper every single word you say	517
3	ZhaoZiLong		403
4	MaMengQi		391
5	HuangHanSheng		383
6	ZhangYiDe		381
7	GuanYunchang		378
8	hydd	Qingyu txdy $\\$ $\text{If my armor breaks, I’ll fuse it back together}$	312
/	flower	sqytxdy!	262
9	Wu_Ren		188
10	Crysfly	$$f(x)=(\sum_{i=0}^{n-1}\frac{y_i}{(x-q^i)\prod_{j\ne i}(q^i-q^j)})\prod_{i=0}^{n-1}(x-q^i)$$	182
11	repoman	$$\prod_{i=0}^{n-1} (1+q^iz) = \sum_{i=0}^n q^{i(i-1)/2}\binom ni_q z^i$$	176
12	alpha1022	$$\frac{1}{n_1!n_2!}(1-y)^{n_1+n_2+2} \left(\sum_{j\ge 0} y^j(t+j)^{n_1} \right) \left(\sum_{j\ge 0} y^j((j+1)-t)^{n_2} \right)$$	161
13	feecle6418	gyh ak ioi	159
14	qwq	$\displaystyle \sum_{i=1}^n [i,i+1,\cdots, i+k] \pmod{10^9+7}$	158
15	Lenstar	orz Qingyu	156
16	zhouhuanyi		153
17	tricyzhkx		149
18	He_Ren		148
19	Sa3tElSefr		146
20	hutality	$$[x^n](1-x)^{-\frac{1}{2}} \exp\left(\frac{x(1+x)}{2-2x}\right)\frac{\left(\frac{2-x}{2-2x}\right)^k}{k!}\cdot\,_0 F _1 \left(;k+1;x\left(\frac{2-x}{2-2x}\right)^2\right)$$	138