| / | Qingyu | | 5127 |
| 1 | larryzhong | | 698 |
| 2 | ZhaoZiLong | | 331 |
| 3 | HuangHanSheng | | 324 |
| 4 | MaMengQi | | 323 |
| 5 | GuanYunchang | | 318 |
| 6 | ZhangYiDe | | 313 |
| 7 | hydd | Qingyu txdy! | Who will guard
the guardians? | Solve more problems. | 警惕境外势力入侵qoj | 254 |
| / | flower | sqytxdy! | 245 |
| 8 | Wu_Ren | | 187 |
| 9 | repoman | $$\prod_{i=0}^{n-1} (1+q^iz) = \sum_{i=0}^n q^{i(i-1)/2}\binom ni_q z^i$$ | 174 |
| 10 | Lenstar | orz Qingyu | 157 |
| 11 | Crysfly | $$f(x)=(\sum_{i=0}^{n-1}\frac{y_i}{(x-q^i)\prod_{j\ne i}(q^i-q^j)})\prod_{i=0}^{n-1}(x-q^i)$$
| 150 |
| 12 | Sa3tElSefr | | 146 |
| 13 | qwq | $\displaystyle \sum_{i=1}^n [i,i+1,\cdots, i+k] \pmod{10^9+7}$ | 145 |
| 14 | feecle6418 | gyh ak ioi | 135 |
| 15 | YaoBIG | | 126 |
| 16 | He_Ren | | 118 |
| 17 | JohnAlfnov | Qingyu Kedavra ! | 113 |
| 17 | zombie462 | <b>123</b> | 113 |
| 19 | hutality | $$[x^n](1-x)^{-\frac{1}{2}} \exp\left(\frac{x(1+x)}{2-2x}\right)\frac{\left(\frac{2-x}{2-2x}\right)^k}{k!}\cdot\,_0 F _1 \left(;k+1;x\left(\frac{2-x}{2-2x}\right)^2\right)$$ | 112 |
| / | alpha1022 | | 111 |
Trainings
Universal Cup